Procedure for implementing Subnets:
Pretty cumbersome, I suppose !!!! Fortunately there is an easier method as you can see below:
Short cut method:
Note that the Subnet mask is /29. That would mean we have stolen five bits from the default mask of a Class C /24 address.
Go five columns deep in the below table, as shown:
The number that you get when you use this method is called the Magic Number. It is 8 in our example.
Your subnets increment on a factor of 8 i.e.
0 - 7
8 - 15
16 - 23
24 - 31
32 - 39
40 - 47
48 - 55
56 - 63
64 - 71
........
........
........
224 - 231
232 - 239
240 - 247
248 - 255
That's 32 networks with 8 IPs for each subnet.
Our IP 192.168.221.37 falls in the 32 - 39 range. So the evaluation goes as:
Use the following table as an aid while calculating subnets:
- Determine the IP address that is assigned by the registry authority
- Based on the organizational and administrative structure, determine the number of subnets that are required
- Depending on the address class and required number of subnets, decide the number of bits that you need to steal from the Host ID
- Evaluate the binary and decimal value of the subnet mask
- Apply the subnet mask to the network IP address to determine the subnet and host addresses
Pretty cumbersome, I suppose !!!! Fortunately there is an easier method as you can see below:
Short cut method:
Note that the Subnet mask is /29. That would mean we have stolen five bits from the default mask of a Class C /24 address.
Go five columns deep in the below table, as shown:
The number that you get when you use this method is called the Magic Number. It is 8 in our example.
Your subnets increment on a factor of 8 i.e.
0 - 7
8 - 15
16 - 23
24 - 31
32 - 39
40 - 47
48 - 55
56 - 63
64 - 71
........
........
........
224 - 231
232 - 239
240 - 247
248 - 255
That's 32 networks with 8 IPs for each subnet.
Our IP 192.168.221.37 falls in the 32 - 39 range. So the evaluation goes as:
Use the following table as an aid while calculating subnets:
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